JavaScript-Developer-I Practice Exams Free & New JavaScript-Developer-I Exam Vce
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To pass the Salesforce Certified JavaScript Developer I exam, candidates need to have a sound understanding of JavaScript programming language and its applications in the Salesforce platform. JavaScript-Developer-I Exam consists of 60 multiple-choice questions and requires a passing score of 68%. JavaScript-Developer-I exam can be taken online, and the candidates have 105 minutes to complete it.
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The Salesforce JavaScript-Developer-I exam consists of 60 multiple-choice questions that are designed to test your knowledge of JavaScript concepts, as well as your ability to apply those concepts in a Salesforce environment. JavaScript-Developer-I exam is timed and you will have 105 minutes to complete it. To pass the exam, you will need to score at least 68% or higher.
To be eligible to take the Salesforce JavaScript-Developer-I Certification Exam, candidates must have a minimum of six months of experience working with JavaScript and Salesforce development. They must also have a good understanding of programming concepts, such as variables, data types, and control structures. Additionally, candidates must have a solid understanding of Salesforce platform concepts, such as objects, fields, and relationships.
Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q123-Q128):
NEW QUESTION # 123
Given a value, which three options can a developer use to detect if the value is NaN?
- A. value === Number.NaN
- B. Object.is(value, NaN)
- C. Number.isNaN(value)
- D. value !== value
- E. value == NaN
Answer: B,C,D
Explanation:
In JavaScript, NaN has some special properties:
* NaN is not equal to anything, including itself.
* Equality operators (==, ===) do not work for detecting NaN.
Check each option:
* A. value === Number.NaN
* Number.NaN is just NaN.
* But NaN === NaN is always false.
* So this expression is never true and cannot be used to detect NaN.
* B. value == NaN
* Same issue. NaN == NaN is always false.
* So this also never detects NaN.
* C. Object.is(value, NaN)
* Object.is is a more precise equality comparison method.
* It treats NaN as equal to NaN: Object.is(NaN, NaN) is true.
* So Object.is(value, NaN) is a valid way to detect NaN.
* D. value !== value
* Because NaN is the only JavaScript value that is not equal to itself , value !== value is true only when value is NaN.
* This is a classic trick for NaN detection.
* E. Number.isNaN(value)
* Number.isNaN is the recommended modern way to check if a value is NaN without coercion .
* It returns true only if value is actually the number NaN.
Therefore, the three correct ways are:
* Object.is(value, NaN)
* value !== value
* Number.isNaN(value)
NEW QUESTION # 124
A developer creates a generic function to log custom messages in the console. To do this, the function below is implemented.
01 function logStatus(status){
02 console./*Answer goes here*/{'Item status is: %s', status};
03 }
Which three console logging methods allow the use of string substitution in line 02?
- A. Assert
- B. Message
- C. Error
- D. Log
- E. Info
Answer: C,D,E
NEW QUESTION # 125
Refer to the following object.
How can a developer access the fullName property for dog?
- A. Dog.fullName ( )
- B. Dog.fullName
- C. Dog, function, fullName
- D. Dog, get,fullName
Answer: B
NEW QUESTION # 126
Refer to the code snippet below:
Let array = [1, 2, 3, 4, 4, 5, 4, 4];
For (let i =0; i < array.length; i++)
if (array[i] === 4) {
array.splice(i, 1);
}
}
What is the value of array after the code executes?
- A. [1, 2, 3, 4, 5, 4]
- B. [1, 2, 3, 4, 5, 4, 4]
- C. [1, 2, 3, 5]
- D. [1, 2, 3, 4, 4, 5, 4]
Answer: D
Explanation:
NEW QUESTION # 127
Refer to the following code that performs a basic mathematical operation on a provided
input:
function calculate(num) {
Return (num +10) / 3;
}
How should line 02 be written to ensure that x evaluates to 6 in the line below?
Let x = calculate (8);
- A. Return Number((num +10) /3 );
- B. Return Number(num + 10) / 3;
- C. Return (Number (num +10 ) / 3;
- D. Return Integer(num +10) /3;
Answer: C
NEW QUESTION # 128
......
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